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Print unknown_str in case of error

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func can return NULL in case of error, but no checking is done when
printing, and unknown_str wasn't being used anywhere.
This commit is contained in:
SiIky 2018-02-17 18:08:27 +00:00
parent 8bfe4b2e28
commit 9ca1ac62f9
1 changed files with 3 additions and 1 deletions
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4
slstatus.c
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@ -87,8 +87,10 @@ main(int argc, char *argv[])
status[0] = '\0'; status[0] = '\0';
for (i = len = 0; i < LEN(args); i++) { for (i = len = 0; i < LEN(args); i++) {
const char * res = args[i].func(args[i].args);
res = (res == NULL) ? unknown_str : res;
len += snprintf(status + len, sizeof(status) - len, len += snprintf(status + len, sizeof(status) - len,
args[i].fmt, args[i].func(args[i].args)); args[i].fmt, res);
if (len >= sizeof(status)) { if (len >= sizeof(status)) {
status[sizeof(status) - 1] = '\0'; status[sizeof(status) - 1] = '\0';